[Free] 2017(Sep) Latesttests Passguide IBM C2020-702 V13 Dumps with VCE and PDF 31-40

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IBM Cognos TM1 10.1 Developer

Question No: 31

A TM1 Operations Console shows a thread which iswaiting to obtain a read lock on a cube. Which thread is blocking it?

  1. A thread which holds a read lock on the cube

  2. A thread which holds a write lock on the cube

  3. A thread which holds an intent to write lock on the cube

  4. A thread which is waiting to write to the cube

Answer: B

Question No: 32

A customer is using TM1 subsets.

Which two statements are true? (Choose two.)

  1. There are three types of subsets: conventional, static, and dynamic.

  2. There are only two access-types for subsets: private and public.

  3. In TM1, there is a notion of a default subset that will appear in the system default view

  4. Subsets can only contain leaf-levelelements.

Answer: B,C

Question No: 33

Which two statements are true about spreading in TM1? (Choose two.)

  1. Spreading is often performed on a single dimension withoutinvolving a cube.

  2. The extend option under spreading allows spreading in more than one direction (e.g., right and up) as one operation.

  3. With spreading, there is only one update action allowed: replace.

  4. Spreading can be used to populate a cube withtest data.

Answer: B,D

Question No: 34

You have developed a sequence of T1 processes connected together by the ExecuteProcess(..) command. To improve the performance of the application, you decide to break up the sub-processes so that they run in their own thread to use cores more efficiently.

Which TM1 object accomplishes this goal?

  1. TM1 RunTl.exe

  2. ExecuteProcessNewThread(..)

  3. ExecuteProcess(…)

  4. BatchProcess.exe

Answer: A

Question No: 35

If vOriginalDate = July 27, and you require vNewDate = Jul2012, which syntax is appropriate to complete this task?

  1. vNewDate=SUBST(vOriginalDate,3,3) | #39;2012#39;;

  2. vNewDate=SUBST(vOriginalDate,3,3) amp; #39;2012#39;;

  3. vOriginalDate=SUBST(vNewDate,3,3) amp; #39;2012#39;;

  4. vNewDate=SUBST(vOriginalDate,3,3) #39;2012#39;;

Answer: A

Question No: 36

Regarding Sandboxes, why do numbers sometimes appear in blue or green?

  1. Green is for values not sent to the server and blue is for uncommitted values.

  2. Green is foruncommitted values and blue is for values not sent to the server.

  3. Green and blue are for uncommitted values depending on client interface used.

  4. Green and blue are for values not sent to the server depending on the client interface used.

Answer: A

Question No: 37

A new member is added to a dimension called Products whichis used in a cube called Sales.

What information is recorded in the audit log?

  1. A change to the total number of members in the Products dimension

  2. A change to the size of the Sales cube

  3. A change to the last updated time of the Products dimension

  4. The name of the new member

Answer: C

Question No: 38

Youhave three elements (A, B, and C) of a dimension in a public subset called THE_SUB. You want to address them in an Area Definition in a rule.

Which syntax should you use?

A. [{#39;A#39;, #39;B#39; , #39;CV}]

  1. [{THE_SUB#39;\}]

  2. [#39;THE_SUB#39;]

D. [A#39;.#39;B#39;.#39;C]

Answer: A

Question No: 39

You are importing data into TM1 using Turbolntegrator. Which three actions are available? (Choose three.)

  1. Create or update a dimension from an external source.

  2. Create or update a cube from an external source.

  3. Re-create a cube to change both data and meta data.

  4. Re-order the dimensions of an existing cube.

  5. Remove a dimension to an existingcube.

Answer: A,B,C

Question No: 40

You are developing a TM1 model for a city aquarium and must add these new elements to the Animal dimension: Amphibians. Frog, andSalamander. Assume that Amphibians is the parent of Frog and Salamander and that you want the children to automatically roll up to the parent.

Which weighting and element type will you assign to each element?

  1. Amphibians Element Type = C. Weight=1 Frog Element Type = N, Weight=0 Salamander Element Type = N, Weight=0

  2. Amphibians Element Type = C, Weight=1 Frog Element Type = N, Weight=1 Salamander Element Type = N, Weight=1

  3. Amphibians Element Type = N, Weights Frog Element Type = N, Weight=0

    Salamander Element Type = N, Weight=0

  4. Amphibians Element Type = P, Weight=1 Frog Element Type = N, Weight=1 Salamander Element Type = N, Weight=1

Answer: B

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