[Free] 2017(Oct) Dumps4cert Testinsides Cisco 200-125 Dumps with VCE and PDF Download 241-250

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CCNA Cisco Certified Network Associate CCNA (v3.0)

Question No: 241 – (Topic 5)

Refer to the exhibit.

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A network administrator is adding two new hosts to SwitchA. Which three values could be used for the configuration of these hosts? (Choose three.)

  1. host A IP address: 192.168.1.79

  2. host A IP address: 192.168.1.64

  3. host A default gateway: 192.168.1.78

  4. host B IP address: 192.168.1.128

  5. host B default gateway: 192.168.1.129

  6. host B IP address: 192.168.1.190

Answer: A,C,F Explanation:

It’s a “router-on-a-stick” configuration. Which means each host in the VLAN must corresponds with the VLAN configured on the sub-interfaces.

VLAN 10 is configured on fa0/0.10 and VLAN 20 on fa0/0.20. So each hosts in VLAN 10 must use fa0/0.10 IP address as their default gateway, each hosts must also be in the

same subnet as fa0/0.10 IP – same with hosts in VLAN 20.

So find out the usable IP addresses on each sub-interfaces – for 192.168.1.78 /27: 192.168.1.65 – .94 and for 192.168.1.130 /26: 192.168.1.128 – .190.

Host A (using port 6 – VLAN 10) must use IP 192.168.1.79, default gateway 192.168.1.78. Host B (using port 9 – VLAN 20) must use IP 192.168.1.190, default gateway 192.168.1.130.

Question No: 242 – (Topic 5)

Which two tasks does the Dynamic Host Configuration Protocol perform? (Choose two.)

  1. Set the IP gateway to be used by the network.

  2. Perform host discovery used DHCPDISCOVER message.

  3. Configure IP address parameters from DHCP server to a host.

  4. Provide an easy management of layer 3 devices.

  5. Monitor IP performance using the DHCP server.

  6. Assign and renew IP address from the default pool.

Answer: C,F Explanation:

The Dynamic Host Configuration Protocol (DHCP) is a network protocol used to configure devices that are connected to a network (known as hosts) so they can communicate on that network using the Internet Protocol (IP). It involves clients and a server operating in a client-server model. DHCP servers assigns IP addresses from a pool of addresses and also assigns other parameters such as DNS and default gateways to hosts.

Question No: 243 – (Topic 5)

What is a valid HSRP virtual MAC address?

A. 0000.5E00.01A3 B. 0007.B400.AE01 C. 0000.0C07.AC15

D. 0007.5E00.B301

Answer: C Explanation:

With HSRP, two or more devices support a virtual router with a fictitious MAC address and unique IP address. There are two version of HSRP.

With HSRP version 1, the virtual router’s MAC address is 0000.0c07.ACxx , in which xx is the HSRP group.

With HSRP version 2, the virtual MAC address if 0000.0C9F.Fxxx, in which xxx is the HSRP group.

Note: Another case is HSRP for IPv6, in which the MAC address range from 0005.73A0.0000 through 0005.73A0.0FFF.

Question No: 244 – (Topic 5)

You are working in a data center environment and are assigned the address range 10.188.31.0/23. You are asked to develop an IP addressing plan to allow the maximum number of subnets with as many as 30 hosts each. Which IP address range meets these requirements?

A. 10.188.31.0/26 B. 10.188.31.0/25 C. 10.188.31.0/28 D. 10.188.31.0/27 E. 10.188.31.0/29

Answer: D Explanation:

Each subnet has 30 hosts lt; 32 = 25 so we need a subnet mask which has at least 5 bit 0s

-gt; /27. Also the question requires the maximum number of subnets (which minimum the number of hosts-per-subnet) so /27 is the best choice.

Question No: 245 – (Topic 5)

Refer to the exhibit.

Dumps4Cert 2017 PDF and VCE

What is the most appropriate summarization for these routes?

A. 10.0.0.0 /21

B. 10.0.0.0 /22

C. 10.0.0.0 /23

D. 10.0.0.0 /24

Answer: B Explanation:

The 10.0.0.0/22 subnet mask will include the 10.0.0.0, 10.0.1.0, 10.0.2.0, and 10.0.3.0 networks, and only those four networks.

Question No: 246 – (Topic 5)

What levels will be trapped if the administrator executes the command router(config)# logging trap 4 (Choose four)

  1. Emergency

  2. Notice

  3. Alert

  4. Error

  5. Warning

Answer: A,C,D,E

Explanation:

The Message Logging is divided into 8 levels as listed below: Level Keyword Description

0 emergencies System is unusable 1 alerts Immediate action is needed 2 critical Critical conditions exist

  1. errors Error conditions exist

  2. warnings Warning conditions exist

  3. notification Normal, but significant, conditions exist 6 informational Informational messages

7 debugging Debugging messages

If you specify a level with the “logging trap level” command, that level and all the higher levels will be logged. For example, by using the “logging trap 4 command, all the logging of emergencies, alerts, critical, errors, warnings will be logged.

Question No: 247 – (Topic 5)

Which two statements describe characteristics of IPv6 unicast addressing? (Choose two.)

  1. Global addresses start with 2000::/3.

  2. Link-local addresses start with FE00:/12.

  3. Link-local addresses start with FF00::/10.

  4. There is only one loopback address and it is ::1.

  5. If a global address is assigned to an interface, then that is the only allowable address for the interface.

Answer: A,D Explanation:

Below is the list of common kinds of IPv6 addresses:

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Question No: 248 – (Topic 5)

What are the Popular destinations for syslog messages to be saved? (Choose three)

  1. Flash

  2. The logging buffer .RAM

  3. The console terminal

  4. Other terminals

  5. Syslog server

Answer: B,C,E Explanation:

By default, switches send the output from system messages and debug privileged EXEC commands to a logging process. The logging process controls the distribution of logging messages to various destinations, such as the logging buffer (on RAM), terminal lines (console terminal), or a UNIX syslog server, depending on your configuration. The process also sends messages to the console.

Note: Syslog messages can be written to a file in Flash memory although it is not a popular place to use. We can configure this feature with the command logging file flash:filename.

Question No: 249 – (Topic 5)

How is an EUI-64 format interface ID created from a 48-bit MAC address?

  1. by appending 0xFF to the MAC address

  2. by prefixing the MAC address with 0xFFEE

  3. by prefixing the MAC address with 0xFF and appending 0xFF to it

  4. by inserting 0xFFFE between the upper three bytes and the lower three bytes of the MAC address

  5. by prefixing the MAC address with 0xF and inserting 0xF after each of its first three bytes

Answer: D Explanation:

The modified EUI-64 format interface identifier is derived from the 48-bit link-layer (MAC) address by inserting the hexadecimal number FFFE between the upper three bytes (OUI field) and the lower three bytes (serial number) of the link layer address.

Question No: 250 – (Topic 5)

Which three are characteristics of an IPv6 anycast address? (Choose three.)

  1. one-to-many communication model

  2. one-to-nearest communication model

  3. any-to-many communication model

  4. a unique IPv6 address for each device in the group

  5. the same address for multiple devices in the group

  6. delivery of packets to the group interface that is closest to the sending device

Answer: B,E,F Explanation:

A new address type made specifically for IPv6 is called the Anycast Address. These IPv6 addresses are global addresses, these addresses can be assigned to more than one interface unlike an IPv6 unicast address. Anycast is designed to send a packet to the nearest interface that is a part of that anycast group.

The sender creates a packet and forwards the packet to the anycast address as the destination address which goes to the nearest router. The nearest router or interface is found by using the metric of a routing protocol currently running on the network. However in

a LAN setting the nearest interface is found depending on the order the neighbors were learned. The anycast packet in a LAN setting forwards the packet to the neighbor it learned about first.

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